Flower Planting With No Adjacent — LeetCode 1042 Python Solution
- Problem
- #1042
- Pattern
- Breadth-First Search
- Reading time
- 3 min
- Source
- leetcode.com
The problem
You have n gardens, labeled from 1 to n, and an array paths where paths[i] = [xi, yi] describes a bidirectional path between garden xi to garden yi. In each garden, you want to plant one of 4 types of flowers.
Example
- Input
- n = 3, paths = [[1,2],[2,3],[3,1]]
- Output
- [1,2,3]
- Explanation
- Gardens 1 and 2 have different types.
Python solution
class Solution:
def gardenNoAdj(self, n: int, paths: List[List[int]]) -> List[int]:
g = defaultdict(list)
for x, y in paths:
x, y = x - 1, y - 1
g[x].append(y)
g[y].append(x)
ans = [0] * n
for x in range(n):
used = {ans[y] for y in g[x]}
for c in range(1, 5):
if c not in used:
ans[x] = c
break
return ansComplexity
| Measure | Complexity |
|---|---|
| Time | O(n + m) |
| Space | O(n + m), where n is the number of gardens and m is the number of paths auxiliary |
Pattern: Breadth-First Search
Expand outward level by level, so the first time you arrive is the shortest way. LeetCode 1042. Flower Planting With No Adjacent is filed here because LeetCode tags it Breadth-First Search, which is the vocabulary this hub collects.
The breadth-first search guide has the Python template for the pattern and the 233 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1042. Flower Planting With No Adjacent?
- LeetCode 1042. Flower Planting With No Adjacent is rated Medium on LeetCode.
- What is the time complexity of LeetCode 1042. Flower Planting With No Adjacent?
- The Python solution on this page runs in O(n + m).
- What is the space complexity of LeetCode 1042. Flower Planting With No Adjacent?
- The Python solution on this page uses O(n + m), where n is the number of gardens and m is the number of paths auxiliary space.
- What topics does LeetCode 1042. Flower Planting With No Adjacent cover?
- LeetCode 1042. Flower Planting With No Adjacent is tagged Depth-First Search, Breadth-First Search and Graph on LeetCode.